# Go gotcha: Why does Go and Pythagoras disagree?

Pythagorean triples are integer solutions to the Pythagorean Theorem,
a^{2} + b^{2} = c^{2}.

A well-known example is (3, 4, 5):

`fmt.Println(3^2+4^2 == 5^2) // true`

The triple (6, 8, 10) is another example, but Go doesn't seem to agree:

`fmt.Println(6^2+8^2 == 10^2) // `**false**

## Answer

The circumflex `^`

denotes bitwise XOR in Go.
The computation written in base 2 looks like this:

0011 ^ 0010 == 0001 (3^2 == 1) 0100 ^ 0010 == 0110 (4^2 == 6) 0101 ^ 0010 == 0111 (5^2 == 7)

Of course, `1 + 6 == 7`

; Go and Pythagoras agree on that.
See Bitwise operators cheat sheet for more about bitwise calculations in Go.

To raise an integer to the power 2, use multiplication:

`fmt.Println(6*6 + 8*8 == 10*10) // `**true**

Go has no built-in support for integer power computations,
but there is a `math.Pow`

function for floating-point numbers.

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