# Go: How to sort in Go

All algorithms in the Go sort package make O(n log n) comparisons in the worst case, where n is the number of elements to be sorted.

## Sort a slice of ints, float64s or strings

Use one of the functions

``````s := []int{4, 2, 3, 1}
sort.Ints(s)
fmt.Println(s) // [1 2 3 4]``````

## Sort with custom compare function

``````family := []struct {
Name string
Age  int
}{
{"Alice", 23},
{"David", 2},
{"Eve", 2},
{"Bob", 25},
}

// Sort by age, keeping original order or equal elements.
sort.SliceStable(family, func(i, j int) bool {
return family[i].Age < family[j].Age
})
fmt.Println(family) // [{David 2} {Eve 2} {Alice 23} {Bob 25}]``````

## Sort custom data structures

``````type Interface interface {
// Len is the number of elements in the collection.
Len() int
// Less reports whether the element with
// index i should sort before the element with index j.
Less(i, j int) bool
// Swap swaps the elements with indexes i and j.
Swap(i, j int)
}``````

Here is an example:

``````type Person struct {
Name string
Age  int
}

// ByAge implements sort.Interface based on the Age field.
type ByAge []Person

func (a ByAge) Len() int           { return len(a) }
func (a ByAge) Less(i, j int) bool { return a[i].Age < a[j].Age }
func (a ByAge) Swap(i, j int)      { a[i], a[j] = a[j], a[i] }

func main() {
family := []Person{
{"Alice", 23},
{"Eve", 2},
{"Bob", 25},
}
sort.Sort(ByAge(family))
fmt.Println(family) // [{Eve 2} {Alice 23} {Bob 25}]
}``````